Solution of Examples

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Example 11

If we consider the potential differences from A to B, we can write

Example 12

The self inductance of air-core solenoid is L₀ = μ₀n²Al = 0.02 mH
The self inductance of iron-core solenoid is L = μn²Al = 10 mH

The relative permeability of iron rod is

Example 13

The coefficient of self-induction of an air-core solenoid is given by

Example 14

The coefficient of self-induction of an air-core solenoid is given by

Example 15

For long co-axial solenoids, the mutual inductance is given by

Example 16

The mutual inductance of the solenoid and the loop is given by

Example 17

The induced emf in the secondary coil is given by

Example 18

Maximum emf is given by

Example 19

Maximum emf is given by

Example 20

(a) Maximum emf is given by

(b) Maximum current I₀ = ε₀ / R = 157.1/100 = 1.571 A

(c) We have to find the instantaneous values of emf and the current.
Instantaneous emf is given by
ε = ε₀ sin ωt = 157.1 sin (314.2t)
Instantaneous current is given by
I = I₀ sin ωt = 1.571 sin (314.2t)

CBSE Electromagnetic Induction ( With Hint / Solution)
Class XII (By Mr. Ashis Kumar Satapathy)
email - [email protected]

Electromagnetic Induction