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Joint Entrance Examination (Main) - 2019

CBSE Guess > JEE (Main) > Eligibility Criteria

JEE (Main) 2019 - Eligibility Criteria

 

Eligibility Criteria :

Age Limit -

For appearing in the JEE (Main) examination there is no age limit for the candidates. The candidates who have passed XII examination in 2017, 2018 or appearing in 2019 irrespective of their age can appear in JEE (Main) Examination - 2019. The candidates should satisfy themselves about the eligibility of age limit requirements of the Institutes in which he/she is desirous of taking admission.

Year of Appearance in Qualifying Examination (QE)-

Only those candidates who have passed their Class 12th Examination or any equivalent qualifying examination in 2017 or 2018; or those who are appearing in their Class 12th Examination or any equivalent qualifying examination in 2019 are eligible to appear in both January, 2019 and April, 2019 JEE (Main)-2019 Examination.

Candidates who passed Class 12th/Qualifying examination in 2016 or before as well as those who will appear in such examination in 2020 or later are not eligible to appear in JEE (Main)– 2019.

Number of subjects in the Qualifying Examination (QE)

Candidates must have taken at least five subjects in class 12th/qualifying examination in order to be eligible for writing JEE (Main)-2019. The candidates who have taken four subjects are not permitted to write JEE (Main)-2019 and if such candidates appear in JEE (Main)-2019 by furnishing wrong information, their rank/result will not be declared.

NTA Score and Compilation of Result of Paper-1 and Paper-2 for JEE (Main)-2019

NTA Score for Paper-1 and Paper-2:

Following shall be applicable for both the attempts

  1. After the JEE (Main)-2019 examinations, the NTA will display Answer Keys & recorded responses of multiple choice questions of Paper-1 and Paper-2 on the NTA's website www.jeemain.nic.in. The date shall be displayed on the NTA's website. The candidates, who are not satisfied with the recorded response, may challenge by filling online application form and paying processing charges of Rs.1000/- per question. The challenge of answer keys will also be accepted online only through the link available on the website www.jeemain.nic.in. by paying processing charges of Rs.1000/- per question. The fee can be paid by credit/debit card. The fee once paid is non-refundable. 6 INFORMATION BULLETIN (1st Attempt) : JEE (MAIN) 2019 The NTA's decision on the challenges shall be final and no further communication will be entertained.
    The result will be compiled on the basis of final answer keys. No grievance with regard to answer key(s) after declaration of result of JEE (Main)-2019 will be entertained.
  2. Evaluation of multiple choice questions of Paper-1 and Paper-2 will be carried out using final answer keys and the raw (actual) marks obtained by a candidate will be considered further for computation of the result of JEE (Main)-2019.
  3. For multi-shift papers, raw marks obtained by the candidates in different shifts/sessions will be converted to NTA Score.

Compilation and display of Result of Paper-1

  1. Compilation and display of Result for First attempt of January session:
    Since, JEE (Main)-2019 Paper-1 first attempt will be conducted in multi-shifts, NTA scores will be calculated corresponding to the raw marks obtained by a candidate as per 2.10.1 (d) above. The calculated NTA scores for all the shifts/sessions will be merged and declared by 31st January, 2019. This shall comprise of the four NTA scores for each of the three subjects (Mathematics, Physics, Chemistry) and the total in Paper-1 of JEE (Main)-2019 for the first attempt.
  2. Compilation and display of Result after Second attempt of April session:
    1. Similarly, JEE (Main)-2019 Paper-1 second attempt will be conducted in multishifts, NTA scores will be calculated corresponding to the raw marks obtained by a candidate as per 2.10.1 (d) above. The calculated NTA scores for the Raw Marks for all the shifts/sessions will be merged for further processing.
    2. The four NTA scores for each of the candidates in Paper-1 of JEE (Main)-2019 for the first attempt as well as for the second attempt will be merged for compilation of result and preparation of overall Merit List / Ranking. Those appeared in both the attempts; their best of the two NTA scores (total) will be considered for further processing.
    3. In case of a tie, i.e. when two or more candidates obtain equal Total NTA Score in JEE (Main)-2019, inter-se merit of such candidates shall be determined in following order:
    4. Rank list for admission to B.E. /B. Tech. (in institutions other than IITs):

      • NTA score of raw mark in Mathematics
      • NTA score of raw mark in Physics
      • NTA score of raw mark in Chemistry
      • Candidates older in age
      • If the resolution is not possible after this criterion, candidates will be given the same rank.
    5. The NTA scores of both the attempts and rank of Paper-1 of JEE (Main)-2019 for all candidates who appeared in first attempt as well as in second will be declared by 30th April, 2019. This shall comprise the four NTA scores obtained by the candidate in first attempt and four NTA scores obtained in second attempt along with the status of those who qualify for appearing in JEE (Advanced)-2019 provided and subject to other conditions of eligibility being met. The rank shall comprise All India rank and All India category rank.

Compilation and display of Result of Paper-2

  1. Compilation and display of Result for First attempt of January session: Since, JEE (Main)-2019 Paper-2 may be conducted in single-shift only, the raw marks obtained by all the candidates who appeared in first attempt will be declared by 31st January, 2019. This shall comprise the actual marks obtained in Paper-2 of JEE (Main)– 2019 for the first attempt.
  2. Compilation and display of Result after Second attempt of April session:
    1. Similarly, JEE (Main)-2019 Paper-2 second attempt may be conducted in single-shift, the raw marks obtained by all the candidates who appeared in second shift as well as for the first attempt will be merged for compilation of result and preparation of overall Merit List / Ranking. Those appeared in both the attempts; their best of the two raw marks will be considered for further processing.
    2. In case of a tie, i.e. when two or more candidates obtain equal Total Marks in JEE (Main)-2019, inter-se merit of such candidates shall be determined in following order:
    3. Rank list for admission to B.Arch./B.Planning (in institutions other than IITs):

      • Candidates obtaining higher marks in Aptitude Test in Paper-2
      • Candidates obtaining higher marks in Drawing Test in Paper-2
      • Candidates older in age
      • If the resolution is not possible after this criterion, candidates will be given the same rank.
    4. The Total raw marks of both the attempts and rank of Paper-2 of JEE (Main)–2019 for all candidates who appeared in first attempt as well as in second will be declared by 30th April, 2019. This shall comprise the total raw marks obtained by the candidate in first attempt as well as in second attempt along with All India rank and All India category rank.

    Note:

  1. All participating institutes that do not use the Centralized Seat Allocation Process will prepare their own ranking based on the performance in JEE (Main)-2019 and other criteria as decided by them.
  2. Only the All India Rank (AIR) is used for admissions through Central Seat Allocation Board (CSAB)/Joint Seat Allocation Authority (JoSAA) to NITs/ IIITs/ CFTIs/ SFIs/ Others, while other ranks are for information purposes.
  3. No score/rank card will be dispatched to the candidates and the candidates are advised to download their score/rank cards from the JEE (Main) website: www.jeemain.nic.in only.
  4. Result of the examination shall be hosted on NTA's website www.jeemain.nic.in.

Admission to Nits, Iiits, Cftis, Sfis, State Engineering Colleges for Participating States and other Participating Institutions

Eligibility for Admission to NITs, IIITs and CFTIs participating through Central Seat Allocation Board

Admission to NITs, IIITs and CFTIs participating though Central Seat Allocation Board will be based on All India Rank as explained above in section 2.10 subject to the condition that the candidate should have secured at least 75% marks in the 12th class examination, or be in the top 20 percentile in the 12th class examination conducted by the respective Boards. For SC/ST candidates the qualifying marks would be 65% in the 12th class examination.

Subject combinations required in the qualifying examination for admission to B.E./B.Tech. & B. Arch./B.Planning Courses in NITs, IIITs, and other CFTIs shall be as under.

Course Required Criteria based on Class 12th / Equivalent qualifying Examination
B.E/B.TECH Passed 10+2 examination with Physics and Mathematics as compulsory
subjects along with one of the Chemistry/Biotechnology/Biology/
Technical Vocational subject.
B.ARCH./B.PLANNING Passed 10+2 examination with Mathematics.

Eligibility for Admission to Other Institutions

The above mentioned policy could also be adopted by other Technical Institutions participating in counselling through JoSAA/CSAB. In case a State opts to admit students in the engineering Colleges affiliated to State Universities, the State may prepare separate rank list based on criteria decided by them.

Number of seats in various institutions

For all admission related procedures/queries, the candidates are advised to refer the website of JoSAA, Central Seat Allocation Board (CSAB) or the concerned State Government/Institute after declaration of ranks of JEE (Main)-2019. The letter/e-mails/grievances/RTI cases/Court cases regarding admission related procedures/queries will not be entertained by NTA.

As per Government of India rules candidates belonging to certain categories are admitted to seats reserved for them based on relaxed criteria. These categories are:

  1. Other Backward Classes (OBC) if they belong to Non Creamy Layer (NCL)
  2. Scheduled Castes (SC)
  3. Scheduled Tribes (ST)
  4. Persons with Disability (PwD)with 40% or more disability

Benefit of reservation for admission to NITs/IIITs and CFTIs shall be given only to those classes/ castes/tribes which are in the respective central list published by the Govt. of India. For admission to State Engineering colleges who have opted for admission through JEE (Main)- 2019, the reservation rules of that State shall apply. The letter/e-mails/grievances/RTI cases/ Court cases regarding reservation criteria will not be entertained by NTA

Seat Allocation Process and Admission Procedure

Candidates shall be offered admission based on their choices and All India Ranks of JEE (Main)- 2019 through a Seat Allocation Process to be announced later. The candidates will be able to make their choices online for branches/programs and institutes at appropriate time. Candidates are advised to regularly visit the JEE (Main) website: www.jeemain.nic.in for latest information.

The verification of documents would be done at the time of Seat Allocation Process/admission. The purpose would be to verify different records regarding identification, age, qualifying examination, state of eligibility, category and disability (if any) of the candidate. On failing to produce any of the authentic documents, the candidate will not be considered for admission.

SC, ST, OBC and PwD candidates will be required to produce original certificate as per prescribed formats given in Appendix -7, issued by the competent authority at the time of Seat Allocation Process as well as at the time of admission, failing which they will not be considered for admission.

Eligibility criteria for appearing in JEE (Advanced) - 2019

(Please refer to JEE (Advanced) website for the latest information)

The minimum academic qualification for appearing in JEE (Advanced) -2019 is that the candidate must have passed in final examination of Class 12th or equivalent qualifying examination (Appendix-3). Those appearing in these examinations in 2019 can also appear in JEE (Advanced)- 2019 provisionally.

All the candidates aspiring to take admission to the undergraduate programs at IITs for the year 2019 will have to appear in the Paper-1 (B. E. /B. Tech.) of JEE (Main)-2019. Based on the performance in Paper-1 (B. E. /B. Tech.) of JEE (Main)-2019, number of top candidates as per the requirement of JEE (Advanced) (including all categories) will be eligible to appear in JEE (Advanced)-2019.

Admissions to IITs will be based only on category-wise All India Rank (AIR) in JEE (Advanced), subject to conditions as defined in JEE (Advanced)-2019 website.

A candidate can attempt JEE (Advanced) a maximum of two times in consecutive years irrespective of whether or not he/she passed the Qualifying Examination. The candidates, who have attempted JEE (Main) /JEE (Advanced) in 2017 or earlier, are NOT ELIGIBLE to appear in JEE (Advanced)-2019.

The candidate who had taken admission in any institute other than IITs in 2018 is eligible to appear in JEE (Advanced)-2019 provided that the candidate satisfies other eligibility criteria.