Example 6. In the given figure. 
is right angle of 
. A semicircle is drawn on AB as diameter. P is any point on AC produced. When joined, BP meets the semi-circle in point D.
Prove that: AB2 = AC.AP + BD.BP.
Solution:-
In
| Subjects | Maths (Part-1) by Mr. M. P. Keshari |
| Chapter 9 | Circle |
| Chapter 10 | Tangents to a circle |
| Chapter 11 | Geometrical Construction |
| Chapter 12 | Troigonometry |
| Chapter 13 | Height and Distance |
| Chapter 14 | Mensuration |
| Chapter 15 | Statistics |
| Chapter 16 | Probability |
| Chapter 17 | Co-ordinate Geometry |
