**Example 6.** In the given figure. is right angle of . A semicircle is drawn on AB as diameter. P is any point on AC produced. When joined, BP meets the semi-circle in point D.

Prove that: AB^{2} = AC.AP + BD.BP.

**Solution:- **

In

Subjects |
Maths (Part-1) by Mr. M. P. Keshari |

Chapter 9 |
Circle |

Chapter 10 |
Tangents to a circle |

Chapter 11 |
Geometrical Construction |

Chapter 12 |
Troigonometry |

Chapter 13 |
Height and Distance |

Chapter 14 |
Mensuration |

Chapter 15 |
Statistics |

Chapter 16 |
Probability |

Chapter 17 |
Co-ordinate Geometry |