Maths by Mr. M. P. Keshari
Example 5. Calculate the arithmetic mean of the following frequency distribution:
| Class Interval | 0-30 | 30-60 | 60-90 | 90-120 | 120-150 | 150-180 | 
| Frequency | 12 | 21 | 34 | 52 | 20 | 11 | 
Solution:-
| Class interval | Frequency | xi | di = xi - 105 | fi di | 
| 0-30 | 12 | 15 | -90 | ![]()  | 
                
| 30-60 | 21 | 45 | -60 | |
| 60-90 | 34 | 75 | -30 | |
| 90-120 | 52 | 105 = a | 0 | -0 | 
| 120-150 | 20 | 135 | 30 | ![]()  | 
                
| 150-180 | 11 | 165 | 60 | |
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                  ![]()  | 
                
Here, a = 105
Arithmetic mean =
| Subjects | Maths (Part-1) by Mr. M. P. Keshari | 
| Chapter 9 | Circle | 
| Chapter 10 | Tangents to a circle | 
| Chapter 11 | Geometrical Construction | 
| Chapter 12 | Troigonometry | 
| Chapter 13 | Height and Distance | 
| Chapter 14 | Mensuration | 
| Chapter 15 | Statistics | 
| Chapter 16 | Probability | 
| Chapter 17 | Co-ordinate Geometry |