**Construction 6.** Construct a triangle ABC in which BC = 6cm, and the attitude through A is 4.5cm. Measure the length of median through A. Write the steps of construction.

**Procedure:- **

- BC = 6cm is drawn and is made downwards with BC of any length.
- is drawn
- Perpendicular bisector RQ of BC is drawn which cut BC at M. and intersect BE at O.
- Taking O as centre and OB as radius, a circle is drawn.
- ML = 4.5cm is cut from RQ.
- A line XY, parallel to BC is drawn through L to intersect the circle at A and A'.

AB, AC, A’B and A’C are joined.

ABC and A’BC are the required triangle

Medium AM = A'M = 5.5cm (app.)

**Construction 7. **Construct a triangle ABC in which BC = 5cm, and median AD through A is of length 3.5cm. Also, determine the length of the altitude drawn from A on the side BC (Write the steps of construction also).

**Procedure:- **

- BC = 5cm is drawn and is constructed downwards.
- BX is drawn perpendicular to BY.
- Q is drawn perpendicular bisector if BC intersecting BX at O and cutting BC at E.
- Taking O as a centre and OB as radius, a circle is drawn.
- Taking E as centre and radius equal to 3.5cm, arc is drawn to cut the circle at A.
- AC and AB are joined
- AD is drawn perpendicular to BC from A to cut BC at D.
- By measuring we find that AD = 3cm.

**Construction 8. **Construction a to a equilateral with side 5cm such that each its sides is 6/7th of the corresponding side of Also draw the circumcircle of .

**Procedure:- **

- A ray QX is drawn making any angle with QR and opposite to P.
- Starting from Q, seven equal line segments QQ
_{1}, Q_{1}R_{2}, Q_{2}Q_{3}, Q_{3}Q_{4}, Q_{4}Q_{5}, Q_{5}Q_{6}, Q_{6}Q_{7}are cut of from QX. - RQ
_{7}is joined and a line CQ_{6}is drawn parallel to RQ_{4}to intersect QR at C. - Line CA is drawn parallel to PR.

ABC is the required triangle.

**Construction 9. **Construct a triangle ABC in which BC = 6cm, and median AD = 5cm. Also construct another triangle BPQ similar to triangle BCA such that the side BP = 3/2BC.

**Procedure:- **

- A line segment BC of length 6cm is drawn.
- At B, is drawn on downwards.
- At B, is drawn
- Perpendicular bisector of BC is drawn which intersect BY at O and BC at D.
- Taking O as a center and OB as a radius a circle passing through B and C is drawn.
- Taking D as a centre and radius 5cm an arc is drawn to intersect the circle at A.
- AB and AC are joined. The required triangle is ABC.
- Taking C as centre and CD as radius an arc is drawn to intersect BC produced at P such that BP = 3/2BC.
- Through P, PQ is drawn parallel to CA meeting BA produced at Q.
- BPQ is the required triangle similar to triangle BCA.

**Consyruction 10. **Construct a quadrilateral ABCD in which AB = 2.5cm, BC = 3.5cm, AC = 4.2cm, CD = 3.5cm and AD = 2.5cm.
Construct another quadrilateral AB’C’D’ with diagonal AC’ = 6.3cm such that it is similar to quadrilateral ABCD.

**Procedure:- **

- A line segment Ac = 4.2cm is drawn.
- With A as a centre and radius 2.5cm, two arcs, one above AC and one below AC are drawn.
- With C as centre and radius 3.5cm, two arcs arc drawn intersecting previous arcs at B and D./li>
- AB, AD, BC and CD are joined ABCD is the required quadrilateral.
- Taking A as a centre and radius 6.3cm an arc is drawn to intersect AC produced at C’.
- Through C’, C’B’ and C’D’ are drawn parallel to CB and CD respectively.

AB’C’D’ is the required quadrilateral similar to ABCD.

Subjects |
Maths (Part-1) by Mr. M. P. Keshari |

Chapter 9 |
Circle |

Chapter 10 |
Tangents to a circle |

Chapter 11 |
Geometrical Construction |

Chapter 12 |
Troigonometry |

Chapter 13 |
Height and Distance |

Chapter 14 |
Mensuration |

Chapter 15 |
Statistics |

Chapter 16 |
Probability |

Chapter 17 |
Co-ordinate Geometry |