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Important Questions

CBSE Guess > Papers > Important Questions > Class XII > 2010 > Maths > Mathematics By Mr. M.P.Keshari

CBSE CLASS XII

Q.4. Prove the following :

2 tan –1(1/2) + tan –1(1/7) = tan –1(31/17).

Solution :

We have, L.H.S. = 2tan –1(1/2) + tan –1(1/7)
= tan –1[{2.(1/2)}/{1 – (1/2)2} + tan –1(1/7)
= tan–1(4/3) + tan –1(1/7)
= tan –1[(4/3 + 1/7)/{1 – (4/3)(1/7)}]
= tan –1[{(28 + 3)/21}/{(21 – 4)/21}]
= tan –1[(31/21)(21/17)]
= tan –1(31/17) = R.H.S. [Proved.]

Q.6. Solve the following for x :

  1. tan –1(2x) + tan –1(3x) = π/4.

    Solution:

    We have, tan –1(2x) + tan –1(3x) = π/4
    Or, tan –1 [(2x + 3x)/{1 – (2x)(3x)}] = π/4
    Or, 5x/(1 – 6x2) = tan π/4
    Or, 5x/(1 – 6x2) = 1
    Or, 5x = 1 – 6x2
    Or, 6x2+ 5x – 1 = 0
    Or, (6x – 1)(x + 1) = 0
    Or, x = 1/6, –1.
    As x = –1 does not satisfy the equation,
    x = 1/6 is the required solution. [Ans.]

  2. tan –1[(x – 1)/(x – 2)] + tan –1[(x + 1)/(x + 2)] = π/4.

    Solution :


    We have, tan –1 [(x – 1)/(x – 2)] + tan –1 [(x + 1)/(x + 2)] = π/4
    Or, tan–1[[{(x –1)/(x –2)} + {(x + 1)/(x + 2)}]/{1– (x –1)/(x –2).(x + 1)/(x + 2)}]
    = π/4
    Or, tan–1{ [{(x –1)(x + 2) + (x + 1)(x –2)}/{(x –2)(x + 2)}]
    /[{(x –2)(x + 2) – (x –1)(x + 1)}/{(x –2)(x + 2)}]} = π/4
    Or, (x2 + x – 2 + x2 – x – 2)/(x2 – 4 – x2 + 1) = tan (π/4)
    Or, (2x2 – 4)/ –3 = 1
    Or, 2x2 – 4 = – 3
    Or, 2x2 – 1 = 0
    Or, x2 = 1/2
    Or, x = ±1/√2. [Ans.]

  3. tan –1[(1 + x)/(1 – x)] = π/4 + tan –1x

    Solution :


    We have, tan –1[(1 + x)/(1 – x)] = π/4 + tan –1x
    Or, tan –1[(1 + x)/(1 – x)] – tan –1x = π/4
    Or, tan–1[{(1 + x)/(1 – x)} – x]/[1 + {(1 + x)/(1 – x)}.x] = π/4
    Or, [{(1 + x) – x (1 – x)}/(1 – x)]/[{(1 – x) + x(1 + x)}= tan π/4
    Or, [(1 + x – x + x2)/(1 – x)]×[(1 – x)/(1 – x + x + x2)] = 1
    Or, (1 + x2)/(1 + x2) = 1
    Or, 1 + x2 = 1 + x2
    Or, 1 = 1
    Therefore, equation has infinitely many solutions. [Ans.]

  4. tan –1{(1 – x)/(1 + x)} – 1/2tan –1 x = 0; x > 0.

    Solution :


    Do yourself. [Ans. x = ±1/√3]

Paper By Mr. M.P.Keshari
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