CBSE Guess > Papers > Important Questions > Class XII > 2007 > Physics > Physics (Electrostatics) By Mr. Ankur Electrostatics By Mr. Ankur FRACTIONAL (STATIC) ELECTRICITY Electricity produced when two bodies are rubbed with each other (due to transfer of electrons). BASIC PROPERTIES OF CHARGES
Integral multiple means e, 2e, and 3e... Thus q= ±ne, where n=0,1,2,3... NOTE 1e = -1.6 ×10-19C 1proton= +1.6 ×10-19C 1 particle or He = +3.2 ×10-19 C Quark's e/3, 2e/3 DIFFERENCE BETWEEN CHARGE AND MASS
COULOMBS LAW: It states that force of attraction or repulsion between two charges is directly proportional to the product of magnitude of charges and inversely proportional to the square of distance between them.
Combining these two factors F = q1 q2 / r 2 or F = k q1 q2 / r2 Where, k = 1/4π ε0 = 9 × 109 N m2 / C2 (S.I) in C.G.S , k = 1 Where ε0 = absolute electrical permittivity of free space ε0 = 8.85 X 10-12 C2 N-1 m-2 NOTE if q1 q2 >0 i.e., both the bodies q1 & q2 are positive or both are negative, then they repel each other. if q1q2 <0 i.e., one is positive and the other is negative, then they attract each other. DEFINITION OF 1 COULOMB--It is that charge which would repel an equal and similar charge place in air 1m apart with a force of 9 X 109 N.
S.I unit of charge = coulomb C.G.S unit of charge = state coulomb 1-coulomb = 3 X 109 state coulomb Q Two alpha particles are separated in air by a small distance of 3.2 X 10-5 m. calculate the Force and the nature of force between them DIELECTRIC CONSTANT (Relative Permittivity)- It is define of a medium as a ratio between the two charges placed at a certain distance apart in air to the force between the same charge placed at same distance apart in the medium.
Thus electric constant of a medium is defined as the ratio of absolute electrical permittivity of the medium to the absolute permittivity of free space. εr or K is the relative permittivity. NOTE Force between the charges in a medium is less than the force between the charges in air. Force in medium < force in air or f(m) < f (air) or K > 1 For water K = 81 therefore Fm = 1 / 81 Fo This shows that the force between two particle get weaker in water that is why sodium chloride get dissolve in water Q A force of F N is observed in air for NaCl and it reduced to F/3 in the non conducting medium , what is the relative permittivity SUPERPOSITION PRINCIPLE-It states that the net force on a charge due to the other charges is equal to the vector sum of individual forces on that charge due to the other charge.
Q1 : Two charged particles of 4q and q are separated by a small distance of x .where should the third point charge of 2q be placed in line joining of them so that in experiences the zero force Q2 : Two charged particles of 4q and -q are separated by a small distance of x .where should the third point charge of 2q be placed in line joining of them so that in experiences the zero force Q3 : Three charged particles of q, 2q, and –q are placed on the vertices of an equilateral triangle of each side 1 m .calculate the coulombs forces on the –q Q4 : Four charged particles of q, 2q, 3q and 4q are placed on the vertices of an square of side 1 m. calculate the coulombs forces at the centre of the square , charge at the centre is q C . CONTINUOUS CHARGE DISTRIBUTION
CAUSE OF CHARGING The cause of charging is actual transfer of electrons from one material to other, when the two substances are rubbed with each other, we provide energy and is used to remove electrons from one substance and is transferred them to the other. ( Note – charging affect the mass of body )
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