Wednesday 19th February 2020
CBSE Guess > Papers > Important Questions > Class X > 2014 > Mathematics > Mathindex > Mathematics By Mr. Ajai Kumar Shukla
CBSE CLASS X
Mathematics
CLASS X MATHS (H.W)
 Use Euclid’s division lemma to show that the square of any positive integer of the form 3m or (3m+1) for some integer m.
 Prove that 2  3√5 is an irrational number.
 On dividing x^{3}  3x^{2} + x + 2 by a polynomial g(x), the quotient & the remainder are x2 &  2x + 4 respectively. Find g(x).
 Find the value of k for which the polynomial x^{4} +10x^{3} +25x^{2}+15x+k is exactly divisible by x+7.
 For what value of x will x^{4}  3x^{3} + 7x^{2}  8x+9 be exactly divisible by x^{2}x+4?
 If the polynomial x^{4}  6x^{3} + 16x^{2 } 25x +10 is divided by another polynomial x^{2}  2x+k the remainder comes out to be x + a. Find the values of k & a.
 Graphically find whether the pair of linear equations: 4x – 3y + 5 = 0 ; 6x4.55 +7.5=0 is consistent or inconsistent.
 Solve :
 Solve: 10/(x +y) +4/(y –x) = 2 , 15/(x +y ) – 7/(y –x) =10
 A number consists of two digits. When it is divided by the sum of the digits, the quotient is 7.The sum of the reciprocals of the digits is 9 times the product of the reciprocals of the digits. Find the number.
 2 men & 5boys can do a piece of work in 4 days while 4 men & 4 boys can do it in 3 days. How long would it take one man or one boy to do it?
 Taxi fare consists of a constant charge together with the charge for the distance covered. A person travelling 15km pays Rs115 for the journey & a person travelling 27km pays Rs199 for it. Find the charges one will have to pay for a journey of 50 km.
 A boat goes 30km upstream & 44km downstream in 10hrs. It can go 40km upstream & 55km downstream in 13hrs. Find the speed of the stream & that of boat in still water.
 Meena went to bank to withdraw Rs2000.She asked the cashier to give her Rs50 & Rs100 notes only. If Meena got 25 notes in all, find how many notes of Rs50 & Rs100 she got.
 Prove each of the following:
 (sec A – cos A) (cot A + tan A) = tan A secA
 (1 + cot A – cosec A)(1 + tan A + sec A) = 2
 tan^{2} A + cot^{2} A + 2 = sec^{2 }Acosec^{2}A
 sec^{4 }A – sec^{2}A = tan^{4} A + tan^{2}A
CBSE Important Questions Class X Mathematics By : Mr. Ajai Kumar Shukla
Submitted By : Mr. Ajai Kumar Shukla,
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