Chapter 10 : Tangents to a circle

Example 6. In the given figure. is right angle of . A semicircle is drawn on AB as diameter. P is any point on AC produced. When joined, BP meets the semi-circle in point D.

Prove that: AB2 = AC.AP + BD.BP.

Solution:-

In

 

Subjects Maths (Part-1) by Mr. M. P. Keshari
Chapter 9 Circle
Chapter 10 Tangents to a circle
Chapter 11 Geometrical Construction
Chapter 12 Troigonometry
Chapter 13 Height and Distance
Chapter 14 Mensuration
Chapter 15 Statistics
Chapter 16 Probability
Chapter 17 Co-ordinate Geometry